Projectile physics problem without the angle given HELP

AI Thread Summary
To solve the projectile physics problem of throwing car keys horizontally at 6.0 m/s from an 80 m high cliff, first calculate the time it takes for the keys to fall using the vertical motion equations, considering the acceleration due to gravity. The time can be determined from the equation for free fall, which does not require an initial vertical velocity. Once the time is known, use it to find the horizontal distance traveled by multiplying the horizontal speed (6.0 m/s) by the calculated time. This approach effectively separates the vertical and horizontal motions to find the distance from the base of the cliff where the keys will land. Understanding this method is crucial for solving similar projectile motion problems.
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projectile physics problem without the angle given! HELP!

You accidentally throw your car keys horizontally at 6.0 m/s from a cliff 80 m high. How far from the base of the cliff should you look for the keys?

Okay so I honestly don't know how to figure this problem out, but I think that I need to use the equations vf=vi+at and Δx=vit

For the second equation, I know that Δx=(6.0)t. I also know that for the first equation I gave, vf=vi+(-9.8)t. I don't know how to figure it out because I feel like I need the angle in order to find out the rest of the information.

I know it sounds like I am a complete slacker, but I really need help with this as soon as possible! Please help me! Thanks!
 
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The angle is given, it is just given indirectly. Reread the first statement.
 


well I know that if the horizontal velocity is 6.0 then 6.0=vi(cosθ), but it doesn't actually give me any other information, and I need to know the vertical velocity in order to solve the problem.
 


Hi,
Just saw your post and though I guess the answer may come a bit late here it is anyway:

You need to work separately the two relevant coordinates (vertical and horizontal).

Calculate the time the keys will take to fall the 80m of the cliff (vertical acceleration of g (due to gravity) with zero initial velocity.

Once you have this time you work the horizontal direction: a constant speed of 6m/s times the time calculated on the previous calculation.

Hope it helps.
 
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