Target #1 and Target #2 are placed as shown. The one on top is made of paper so that an object hitting it will pass right through without its motion being disturbed. At what velocity and angle must you shoot an arrow so that it will pass through target #1 and land on target #2? Assume that the launch and land heights are the same.
Range equation is Vo^2 sin 2θ / g
horizontal velocity = Vo cos θ
vertical velocity - Vo sin θ
That's all I can think of!
The Attempt at a Solution
I'm thinking that the horizontal velocity is the range, but I can't even get the range since I don't have Vo and θ. I usually find vertical and horizontal components, but I don't have Vo and θ. Is the distance from the arrow to target #2 (100 m) the range, since it's X? I'm really not sure how to approach this problem, and projectile motion isn't my cup of tea...
Would you use trig to find horizontal velocity since you have distance half the trip in the air and the height from the first target to the floor?
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