Projectile Problem - Time of Peak

Click For Summary

Homework Help Overview

The problem involves determining the time a fireworks rocket will coast before reaching its peak height, given an initial upward speed of 58 m/s. The discussion centers around the application of kinematic equations in the context of projectile motion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the use of the equation t=v0z/g and question whether the initial velocity should be considered as 58 m/s or 0 m/s. There is also discussion about the necessity of an angle of launch and its impact on the time to peak.

Discussion Status

Some participants have provided calculations based on different launch angles, while others assert that for a vertical launch, the angle is effectively 90 degrees. There is a mix of interpretations regarding the role of the angle in this specific scenario, and some guidance has been offered regarding the correct application of the kinematic equation.

Contextual Notes

Participants are considering the implications of launch angles on the time to peak, with some suggesting that the angle is not necessary for a vertical launch. The discussion reflects varying assumptions about the problem setup.

courtney1121
Messages
68
Reaction score
0
If a fireworks rocket has an initial upward speed of 58 m/s when launched, for how long will it coast before reaching its peak?

So could I use the equation t=v0z/g?

When I use this I get the peak to be 5.9s. Is v0z = 58 m/s or would that be 0? Am I approaching this correctly?
 
Physics news on Phys.org
Anyone have an idea?
 
well you need an angle because time would depend on the angle you use. For example if you launched the rocket at a 50 degree angle the time to reach its peak would be 58sin50 / 9.81 = 4.42 secs. But if you launched the rocket at a 70 degree angle it would be 58sin70 / 9.81 = 5.55 seconds. So you would have to specify the angle.
 
oh ok, so even if you shoot the firework straight up, it still needs an angle?
 
well straight up it would be 90 degrees. 58sin 90 / 9.81 = 5.912 seconds.
 

Similar threads

Replies
40
Views
3K
Replies
5
Views
2K
Replies
27
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
2K
Replies
16
Views
3K
  • · Replies 53 ·
2
Replies
53
Views
5K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 18 ·
Replies
18
Views
2K