Projectile question - X and Y direction

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SUMMARY

The discussion centers on calculating the time a bullet is in the air when fired at a 60° angle with an initial velocity of 200 m/s. The horizontal and vertical components of the initial velocity are determined using the equations Vix = Vicosθ and Viy = Visinθ, resulting in Vix = 100 m/s and Viy = 173.2 m/s. The time of flight is calculated using the equation Y = (Viy)t - (1/2)at², leading to a conclusion of 35.4 seconds, assuming the bullet is fired from ground level. However, the discussion highlights that the problem lacks sufficient information regarding the initial vertical position of the bullet.

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anthony123456
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A bullet is fired at an angle of 60° with an initial velocity of 200 m/s. How long is the bullet in the air?

Homework Equations



Vix = Vicosθ
Viy = Visinθ

Vfy = Viy + ayΔt
Xf = xi + VixΔt

... Ask for more equations available...

The Attempt at a Solution



Vix = 200cos60° = 100m/s
Viy = 200sin60° = 173.2 m/s

X variables:
xi = 0m
xf = ?
Δt =?
Vix = 100m/s


Y variables:
Yi = ?
Yf = 0m
Δt =?
Viy = 173.2m/s
Vfy = ?
a = -9.8m/sANSWER HAS TO EQUAL 35.4 SECONDS, ACCORDING TO MY PHYSICS TEACHER!
 
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Relevant Equation
Y=(V_{iy})t-\frac{1}{2}at^2
 
The question is unanswerable, because you are not given knowledge about the initial y-component position of the bullet or the landscape into which the bullet will travel.

But if we assume your teacher meant to describe a world in which bullets are fired from ground level into landscapes that are perfectly flat, we can proceed. If that is the case, Yi = 0. If you need additional help, just ask for it.
 

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