A bullet is fired at an angle of 60° with an initial velocity of 200 m/s. How long is the bullet in the air?(adsbygoogle = window.adsbygoogle || []).push({});

2. Relevant equations

Vix = Vicosθ

Viy = Visinθ

Vfy = Viy + ayΔt

Xf = xi + VixΔt

... Ask for more equations available....

3. The attempt at a solution

Vix = 200cos60° = 100m/s

Viy = 200sin60° = 173.2 m/s

X variables:

xi = 0m

xf = ?

Δt =?

Vix = 100m/s

Y variables:

Yi = ?

Yf = 0m

Δt =?

Viy = 173.2m/s

Vfy = ?

a = -9.8m/s

ANSWER HAS TO EQUAL 35.4 SECONDS, ACCORDING TO MY PHYSICS TEACHER!

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# Projectile question - X and Y direction

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