Projectiles launched from an angle

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Projectile motion problems can be solved using vertical displacement and initial velocity to find the launch angle. The vertical and horizontal components of motion are treated separately, with horizontal motion being uniform and vertical motion experiencing constant acceleration. To find the initial velocity given total horizontal and vertical displacements and the launch angle, specific kinematic equations and trigonometric relationships are applied. The discussion includes a specific example of a ball launched at a 35-degree angle that clears a 21.0m wall 130.0m away, prompting inquiries about the correct formulas to use. Clarifications on terms like vertical height and horizontal velocity are also sought to enhance understanding of the calculations involved.
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I know how to solve projectile problems when they are launched from an angle if I know the angle and the initial velocity, I need to know:

a. Can you use the vertical displacement (m) and the initial velocity(m/s) to find the angle?

b. How do you find the initial velocity when you know the total horizontal displacement and the total Vertical displacement and the angle at which it is launched? (i.e. a ball is launched at a 35.0 degree angle and it clears a 21.0m wall 130.0m away, what is the initial velocity at which the ball was thrown?)
 
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Answer A

1. Yes you can.

2.Try this way

v_end^2=v_h^2+2a(x-x_0)
0=v_h^2+2g(0-h)
(2g(0-h))^1/2=v_h

sinX=V_h/initial velocity
 
But I don't know the Final velocity or the initial velocity of the horizontal.
 
The Horizontal has constant speed. Vx is constant.

The Velocity of the projectile motion can be done with its components, where component x is an uniform speed movement, and component y will experience constant acceleration movement.
 
Last edited:
alanna said:
I know how to solve projectile problems when they are launched from an angle if I know the angle and the initial velocity, I need to know:

a. Can you use the vertical displacement (m) and the initial velocity(m/s) to find the angle?

b. How do you find the initial velocity when you know the total horizontal displacement and the total Vertical displacement and the angle at which it is launched? (i.e. a ball is launched at a 35.0 degree angle and it clears a 21.0m wall 130.0m away, what is the initial velocity at which the ball was thrown?)
For b, the attached picture should be a correct method of finding the initial velocity, using the appropriate formulae of motion. (v^2 - u^2 = 2as and basic trigonometric..)
 

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Pseudo Statistic said:
For b, the attached picture should be a correct method of finding the initial velocity, using the appropriate formulae of motion. (v^2 - u^2 = 2as and basic trigonometric..)

Thank you so much, I've been stuck on a problem like this forever.
 
sorry but what do u mean when u use v_h?

vertical velocity? vertial height (S_y)?

Sin x = ? U_y / U_x ?
 
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