Projecting Area and Flux of Hemisphere, Frustum & Cone

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Homework Help Overview

The discussion revolves around the projection of area and the calculation of flux through various geometric surfaces, specifically a hemisphere, frustum, and cone, within the context of a uniform electric field.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster seeks clarification on the concept of flux through different surfaces, specifically asking for confirmation on the flux through a hemisphere and requesting explanations for a frustum and cone. Some participants provide diagrams and suggest that the flux can be calculated based on the surface area and the electric field.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of how to calculate flux for the hemisphere and frustum. There is a request for confirmation on the hemisphere's flux calculation, and questions about the orientation of the hemisphere are raised, indicating a productive examination of the topic.

Contextual Notes

Participants express confusion regarding the calculations for the frustum and hemisphere, highlighting the need for further examples and clarification on assumptions related to surface orientation.

stronghold.mr
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PREVIOUS POST ----https://www.physicsforums.com/showthread.php?t=165844
THIS POST HELP ME OUT TO SOME EXTENT BUT I AM STILL MESSED UP...

I am messed up with the concept of projection of area of different surfaces and flux through different surfaces...

Please someone explain it with some examples such as -

1. Hemisphere (I AM GETTING --- FLUX = E pi r^2 ) PLEASE CONFIRM
2. Frustum (not getting)
3. Cone (not getting)

we have to find flux through all these surfaces (The field E is uniform)
 
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sorry about my English ...
- What came in must come out ...
3.
this is your Diagram:
(N.B. the dots in the cone are just to give it shape)

E
-->.../.\
-->../...\
-->./...\ <---- cone
-->/____\___________ <- table

...
E
-->.../!
-->../.!
-->./..! <---- half cone
-->/__! ___________ <- table
you have a triangle so the flux is :(surface of triangle) * (E) = ...
you can work out the same with othe problems .
 
thanks for ur reply

but can u please explain it for frustum and hemisphere

not getting the answer in case of frustum

and please confirm hemisphere one

thanks
 
What is the orientation of the hemisphere ?
attachment.php?attachmentid=26240&d=1275727066.jpg

case 1 :
flux = (surface of semi Circle )*E
or
case 2 :
flux = (surface of a Circle )*E
 

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  • Flux Problem.JPG
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