Projecting to the range of a matrix

  • Thread starter Thread starter mikael27
  • Start date Start date
  • Tags Tags
    Matrix Range
Click For Summary
SUMMARY

The discussion centers on finding the matrix B that represents the projection onto the subspace V = span({(0, 1, 1)t}) parallel to the subspace U = span({(1, 2, 1)t, (1, 0, 0)t}) in R3. The proposed solution involves using the relationship B = C(DC)−1D, where C is a matrix with range U and D is a matrix whose nullspace is V. This approach is confirmed as correct for determining the projection matrix.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically subspaces and spans.
  • Familiarity with matrix operations, including multiplication and inversion.
  • Knowledge of projection matrices and their properties.
  • Experience with nullspaces and their significance in linear transformations.
NEXT STEPS
  • Study the derivation and properties of projection matrices in linear algebra.
  • Learn about the computation of nullspaces and their applications in projections.
  • Explore the concept of matrix inversion and its role in linear transformations.
  • Investigate the geometric interpretation of projections in R3.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as anyone involved in computational mathematics or applied mathematics requiring an understanding of matrix projections.

mikael27
Messages
59
Reaction score
0

Homework Statement



Let U = span({(1, 2, 1)t, (1, 0, 0)t}) and V = span({(0, 1, 1)t}) be subspaces of
R3. Find the matrix B representing the projection onto V parallel to U.

Homework Equations





The Attempt at a Solution



If a matrix C with range U and and a matrix D whose nullspace is V then we can find the projection of matrix B

B = C(DC)−1D

Is my thought correct?
 
Physics news on Phys.org
can anyone help ?
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
15
Views
2K
Replies
8
Views
3K