Proof by Induction: Explaining Step 3 to 4 | Math Homework

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SUMMARY

The discussion focuses on the transition from step 3 to step 4 in a proof by induction involving the expression (-x(n+1)). A key correction was identified in the inequality, specifically the placement of parentheses in the expression ##\Pi_{i = 1}^{n + 1} (1 - x_i) \ge \left(1 - \sum_{i =1}^n x_i\right)(1 - x_{n + 1})##. The removal of (-x(n+1)) is clarified as a result of combining terms in the inequality, which is further supported by the application of Boole's Inequality. This correction is essential for understanding the proof's validity.

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Robb
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Homework Statement


Attached are notes from class. Can someone please explain what happens to (-x(n+1)) in step 3 to step 4. Not sure why it goes away. Thanks!

Homework Equations

The Attempt at a Solution

 

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Robb said:

Homework Statement


Attached are notes from class. Can someone please explain what happens to (-x(n+1)) in step 3 to step 4. Not sure why it goes away. Thanks!

Homework Equations

The Attempt at a Solution

Your notes (did you take them?) aren't very helpful, as there is a relatively minor error in them -- a misplaced parenthesis.
Here's the corrected version of step 2.
##\Pi_{i = 1}^{n + 1} (1 - x_i) \ge \left(1 - \sum_{i =1}^n x_i)\right)(1 - x_{n + 1})##
The right side of your inequality is incorrect, due to the parentheses being in the wrong place. One of the factors in the inequality is ##(1 - \sum_{i = 1}^n x_i)## and the other is ##(1 - x_{n + 1})##

The error is corrected in step 3. Now, to answer your question, what do ##-\sum_{i = 1}^n x_i## and ##-x_{n + 1}## combine to make?
 
Last edited:
the only things I'd add are

i.) if OP has proven Union Bound (Boole's Inequality), this result follows almost immediately -- though you need to think carefully about sets and coin tossing to get the result. - - - -
edit: geometric mean idea ran into too much trouble. Boole's Inequality still gives a very quick and satisfying answer.
 
Last edited:

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