Proof: f is Strictly Increasing in an Interval with f' > 0 | Homework Analysis

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Homework Statement


If f is differentiable in an interval I and f' >0 throughout I, except possibly at a single point where f' >=0 then f is stictly incresing on I


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The Attempt at a Solution



Ok what I have is I let f'(x) >0. I let a and b two points in the interval with a<b. then for some x in (a,b) with
F'x= (f(b)-f(a))/b-a
but f'(x)>0 for all x in (a,b) so
(f(b)-f(a))/(b-a) >0

since b-a>0 it follows that f(b)>f(a)


What you can see I have proved that it is incresing in the interval but I am not sure what to do when f'=0 any help would be much appreciated as I have been told that it is not fully correct.
 
on Phys.org
Do you have the integral and the fundamental theorem of calculus available to you, or only the derivative?
 
Ah its cool. I managed to work it out. And I am pretty convinced that it works.
Thanks anyway appreciate it.