Proof Help: Directional Derivatives

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SUMMARY

The discussion focuses on disproving the statement that for any nonlinear function f: R^2->R^2 and vectors a, v in R^2, the equation f(a+v) - f(a) = [Df(a)]v holds true. Participants emphasize the importance of finding a counterexample to demonstrate the falsity of this statement. They suggest using simple nonlinear functions, such as those with squared terms, and specific points to illustrate the failure of the equation. The key takeaway is that demonstrating the equation's failure for a single nonlinear function suffices to disprove the general claim.

PREREQUISITES
  • Understanding of directional derivatives and their notation
  • Familiarity with nonlinear functions in R^2
  • Knowledge of the concept of differentiability and the derivative operator [Df(a)]
  • Basic logic and proof techniques in mathematics
NEXT STEPS
  • Explore the properties of directional derivatives in nonlinear functions
  • Investigate specific examples of nonlinear functions, such as f(x, y) = x^2 + y^2
  • Learn about the implications of the linearity of functions in calculus
  • Study proof techniques for disproving universal statements in mathematics
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Mathematics students, educators, and researchers interested in calculus, particularly those focusing on the properties of nonlinear functions and directional derivatives.

rman144
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Prove the following is not true:

Let f : R^2->R^2 be a nonlinear function. For any vectors a,v in R^2;

f(a+v)-f(a)=[Df(a)]v


In terms of my attempt, I've been trying to find some combination of a and v that ensure this fails, but so far the best I've come up with is to start with:

[Df(a)]v=lim{h->0} (f(a+hv)-f(a))/h

And then trying to show that f(a+v)-f(a) is the same thing only as h->1; again, no luck. I really just need a hint or two as to which way to approach the proof.
 
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To show an equation is false you don't have to prove a big theorem. You just have to find an example where it doesn't work. Have you actually tried any examples? Take something simple with a squared term, an easy point and an easy unit vector. Almost anything you try should give a counterexample. Just show the equation you are given doesn't work using the formula for directional derivative.
 
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.
 
rman144 said:
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.

Read the text yourself. It asks you to prove a theorem is not true.
 
You can use that f is non-linear. What does that mean? Either
1) There exist x, y so that f(x+y) is NOT f(x)+f(y)

2) There exists x, c a constant so that f(cx) is NOT cf(x).

Cleverly pick your point a to be one at which f is 'not linear' so to speak (i.e. you can use a to demonstrate f is non-linear by one of these).
 
rman144 said:
Read the text; finding a counter example for one function f simply proves that it doesn't hold for that ONE function f; the problem asks to show this is true for ANY nonlinear function.
This is basic logic. You need to disprove a statement of the form "for all nonlinear functions f and vectors a,v: ...". This means finding one particular nonlinear function f and particular vectors a and v such that ... does not hold, is enough.
 

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