Proof: Let C be a Square Matrix, Show if C^(k+1)=0, then I-C is Nonsingular

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SUMMARY

For a square matrix C, if C^(k+1) = 0, then the matrix I - C is nonsingular. The proof demonstrates that the inverse of I - C can be expressed as (I - C)^-1 = I + C + C^2 + ... + C^k. This conclusion is reached by showing that the product (I - C)(I + C + ... + C^k) simplifies to I, confirming the nonsingularity of I - C.

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  • Understanding of square matrices and their properties
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  • Familiarity with matrix exponentiation
  • Basic concepts of linear algebra
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Homework Statement


Give a proof:
Let C be a square matrix.
Show if C^(k+1)=0,
then I-C is nonsingular and (I-C)^-1=I+C+C^2+...+C^k.


Homework Equations


I don't know.
I can't find a theorem that will help me.


The Attempt at a Solution


I know if a matrix is nonsingular, it has an inverse.
 
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You need no theorem, one can see it directly, because , (I-C)(I+C+...+C^k)=I-C^(k+1)=I which means, that I-C is invertable, and the inverse is the above.
 

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