Proof of an inverse Laplace Transform needed please

Click For Summary
SUMMARY

The discussion centers on finding the inverse Laplace Transform of the function \(\frac{s}{(s-a)(s-b)}\). The solution is established as \(\frac{ae^{at} - be^{bt}}{a-b}\). Participants suggest evaluating the residues of the function at \(s = a\) and \(s = b\) using L'Hôpital's theorem to derive the inverse transform effectively.

PREREQUISITES
  • Understanding of Laplace Transforms
  • Familiarity with L'Hôpital's theorem
  • Knowledge of residue calculus
  • Basic differential equations
NEXT STEPS
  • Study the properties of Laplace Transforms in detail
  • Learn how to apply L'Hôpital's theorem in complex analysis
  • Explore residue calculus for evaluating integrals
  • Practice inverse Laplace Transform problems with varying functions
USEFUL FOR

Students and professionals in mathematics, engineering, and physics who are working with Laplace Transforms and need to solve differential equations or analyze system behavior.

raytrace
Messages
9
Reaction score
0

Homework Statement



[tex]\frac{s}{(s-a)(s-b)}[/tex]

Homework Equations



Now I know that it results in:

[tex]\frac{ae^(at)-be^(bt)}{a-b}[\tex]<br /> <br /> <h2>The Attempt at a Solution</h2><br /> <br /> OK, I don't have the slightest clue where to begin. Could someone point me in the right direction? I've looked at all the Transforms on the table on the back of the book but none of them give me a clue as to how to deal with a [tex]\frac{s}{s-a}[\tex] situation.[/tex][/tex]
 
Physics news on Phys.org
Evaluate the residues of

s/[(s-a)(s-b)] exp(st)

at s = a and s = b using L'Hôpital's theorem.
 
Count Iblis said:
Evaluate the residues of

s/[(s-a)(s-b)] exp(st)

at s = a and s = b using L'Hôpital's theorem.

Thanks for the quick reply, will try that out.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
9
Views
3K