Proof of Cauchy Schwarz for complex numbers

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Homework Help Overview

The discussion revolves around proving the Cauchy-Schwarz inequality for complex numbers, specifically focusing on the expression where t is defined as /. Participants are exploring the manipulation of this expression and the implications of complex conjugates in the context of inner products.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to simplify the expression and are discussing the role of the conjugate in the inner product. There are questions about the meaning of the notation used, particularly the asterisk (*) which denotes the conjugate.

Discussion Status

The discussion is ongoing, with participants providing insights into the manipulation of the expression and clarifying terminology. There is an emphasis on simplifying the expression further and understanding the implications of the conjugate in the context of the problem.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can share or the methods they can use. The discussion includes assumptions about the properties of inner products in complex spaces.

dispiriton
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Homework Statement


I am told to try and solve <x - ty, x - ty> where t = <x,y>/<y,y>
However, I am stuck at that equation and unable to manipulate it to get rid of the *

Homework Equations





The Attempt at a Solution


<x - ty, x - ty> = <x,x> - <x,ty> - <ty,x> + <ty,ty>
= mod(x)^2 + mod(y)^2 (t^2) - t*<x,y> - (<x,ty>)*
 
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dispiriton said:

Homework Statement


I am told to try and solve <x - ty, x - ty> where t = <x,y>/<y,y>
However, I am stuck at that equation and unable to manipulate it to get rid of the *

Greetings dispiriton! What do you mean by "the *"?
 
dispiriton said:
<x - ty, x - ty> = <x,x> - <x,ty> - <ty,x> + <ty,ty>
= mod(x)^2 + mod(y)^2 (t^2) - t*<x,y> - (<x,ty>)*

You could simmplify this further by working out <x,ty>*. Try to get thet out of the inproduct.

Then, make the substitution t=<x,y>/<y,y>...
 
Undoubtedly0 said:
Greetings dispiriton! What do you mean by "the *"?

Its sort of like the "bar" where it is the conjugate.
 

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