Proof of law of sines using cross product

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The discussion focuses on proving the law of sines using the vector cross product. Participants suggest starting with the definitions of the law of sines and the cross product, particularly its relation to sine through the formula involving magnitudes and angles. They recommend representing the sides of a triangle as vectors and using cross products to establish relationships between angles and sides. Additionally, there is a mention of connecting the proof to the concept of the circumradius (2R) of the triangle. The conversation emphasizes the need for clarity on the definition of the cross product being used to facilitate the proof.
BelieverOf143___
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Homework Statement
Prove the law of sines using the vector cross product
Relevant Equations
Is there some relation between the vector cross product and sin?
Can somebody please give me a hint for this problem?
 
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BelieverOf143___ said:
Homework Statement: Prove the law of sines using the vector cross product
Relevant Equations: Is there some relation between the vector cross product and sin?

Can somebody please give me a hint for this problem?
What problem? What do you know about how to compute cross products?
 
Well for the cross product I found a general way on how to evaluate the cross product for two dimensions (a general formula for the value of the z-coordinate)
 
I know how to compute them
 
When given a task like this, you have to start with the definitions you are expected to work from. State the law of sines and the definition of the cross product you've been given.
If the latter is in terms of its magnitude being ##|\vec a||\vec b|\sin(\theta)##, try combining that with representing a triangle as a summation of two vectors.
 
Nice way to prove the law of sines but what about to get ##2R## in the same spirit? :)
 
BelieverOf143___ said:
Can somebody please give me a hint for this problem?
Consider the sides of the triangle as vectors. Take one of them. It is the sum of the other two. Take the cross product of that side by itself.
 
wrobel said:
Nice way to prove the law of sines but what about to get ##2R## in the same spirit? :)
With the standard notations, let ##D## be the other end of the diameter from ##A##, then ##\overrightarrow{DB}=\overrightarrow{DA}+\overrightarrow{AB}##. Take cross product with ##\overrightarrow{DB}##, and use that the angle at ##D## is equal to the one at ##C##.
 
martinbn said:
With the standard notations, let D be the other end of the diameter from A, then DB→=DA→+AB→. Take cross product with DB→, and use that the angle at D is equal to the one at C.
this is essentially the same standard proof that everybody knows
 
Last edited:
  • #10
BelieverOf143___ said:
Is there some relation between the vector cross product and sin?
Not sine, the Law of Sines. For any triangle the length of a side is proportional to the sine of the angle opposite to it.
 
  • #11
Herman Trivilino said:
Not sine, the Law of Sines. For any triangle the length of a side is proportional to the sine of the angle opposite to it.
I see no reason to doubt @BelieverOf143___ understands that. If the vector product rule can be used to prove the law of sines then there must be some connection between the vector product and the sine function.
The OP's question indicates ignorance of such a connection. So to assist, we need to know what definition of the cross product is to be used.
 

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