Proof of Nonsingular Matrices: Linear Algebra

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SUMMARY

The discussion centers on the proof of nonsingular matrices in linear algebra, specifically addressing the relationship between two nonsingular nxn matrices A and B. The user asserts that if A and B are nonsingular, then the product AB is also nonsingular, and attempts to prove that (AB)-1 = B-1A-1. The user initially misinterprets the notation, confusing A-1 with the inverse operation, leading to an incorrect proof structure. The correct relationship is established as (AB)-1 = B-1A-1, confirming that the order of multiplication matters in matrix inverses.

PREREQUISITES
  • Understanding of matrix operations, specifically multiplication and inversion.
  • Familiarity with the definition of nonsingular matrices and their properties.
  • Knowledge of linear algebra concepts, particularly the identity matrix.
  • Ability to manipulate and prove relationships involving matrices and their inverses.
NEXT STEPS
  • Study the properties of matrix inverses, focusing on the relationship (AB)-1 = B-1A-1.
  • Explore the implications of nonsingular matrices in linear transformations.
  • Learn about the identity matrix and its role in matrix multiplication.
  • Review proofs related to linear algebra to strengthen understanding of matrix properties.
USEFUL FOR

Students of linear algebra, mathematics educators, and anyone seeking to deepen their understanding of matrix theory and proofs involving nonsingular matrices.

Mdhiggenz
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Homework Statement


http://i48.tinypic.com/2qu14ax.jpg

Can you guys explain whether or not my proof would be sufficient. My thought process was to start with the definition.

So if A is nonsingular is means that A has an inverse such that

A=A-. I used that same thinking for B. B=B-

Then using the question which states. IF A and B are nonsingular nxn matrices then AB is also nonsingular and (AB)-=A-B-

I thought it would be easier to prove the right side so I started with AB=A-B-

and used the relationship A=A- and B=B- to show that both sides are equal. However I found the proof online, and they did something slightly different.

Am I incorrect, if so where did I go wrong in my thinking?

Thanks

Homework Equations


The Attempt at a Solution

 
Last edited by a moderator:
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Non-singular does not mean that A = A-1

It means that there is an inverse A-1 such that AA-1 = A-1A = I
 
And (AB)-1 = B-1A-1, not A-1B-1
 

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