Proof of Parseval's Identity for a Fourier Sine/Cosine transform

Click For Summary
SUMMARY

The discussion centers on proving Parseval's Identity for the Fourier Sine and Cosine transforms, specifically the formula 2/π [integration 0 to ∞] Fs(s)•Gs(s) ds = [integration 0 to ∞] f(x)•g(x) dx. The term '2/π' is questioned, with suggestions that it arises from the factor √(2/π) appearing in the integral setup. Participants reference their successful proofs of the Complex Fourier Transform identity and seek clarity on the definitions of terms like F_C(s) and G_C(s) to facilitate understanding.

PREREQUISITES
  • Understanding of Fourier Sine and Cosine transforms
  • Familiarity with Parseval's Identity in the context of Fourier analysis
  • Knowledge of complex numbers and their properties in Fourier transforms
  • Ability to perform integration over infinite intervals
NEXT STEPS
  • Research the derivation of Parseval's Identity for Fourier Sine and Cosine transforms
  • Study the relationship between complex Fourier transforms and their real counterparts
  • Examine the role of normalization factors like √(2/π) in Fourier analysis
  • Explore detailed examples of applying Parseval's Identity in practical scenarios
USEFUL FOR

Mathematicians, physicists, and engineering students focusing on Fourier analysis, particularly those interested in signal processing and harmonic analysis.

tanaygupta2000
Messages
208
Reaction score
14
Can anyone help me with the Proof of Parseval Identity for Fourier Sine/Cosine transform :

2/π [integration 0 to ∞] Fs(s)•Gs(s) ds = [integration 0 to ∞] f(x)•g(x) dx

I've successfully proved the Parseval Identity for Complex Fourier Transform, but I'm unable to figure out from where does the term '2/π' comes in the Parseval formula for Fourier Sine and Cosine Transform.
Any help will be appreciated.
Thank You.
 
Physics news on Phys.org
It would help if you defined your terms and variables.
 
  • Like
Likes   Reactions: BvU
I'm having difficulty in proving this. According to me, the term '2/π' is not coming.
Parseval%20identity.jpeg
 

Attachments

  • Parseval%20identity.jpeg
    Parseval%20identity.jpeg
    34.7 KB · Views: 2,123
It would help if the definitions were given for ##F_C(s),G_C(s)##, etc.
 
Refer this picture
Screenshot_2019-03-06-08-13-58-035_com.adobe.reader.jpeg
 

Attachments

  • Screenshot_2019-03-06-08-13-58-035_com.adobe.reader.jpeg
    Screenshot_2019-03-06-08-13-58-035_com.adobe.reader.jpeg
    52.6 KB · Views: 2,694
I haven't tried to work it through, but it looks like the factor ##\sqrt{\frac{2}{\pi}}## appearing twice in setting up the integral leads to ##\frac{2}{\pi}##.
 
I've proved it the same way as Complex transform identity.
IMG_20190307_063526.jpeg
 

Attachments

  • IMG_20190307_063526.jpeg
    IMG_20190307_063526.jpeg
    22.7 KB · Views: 2,145
tanaygupta2000 said:
I've proved it the same way as Complex transform identity.View attachment 239848
Please post attachment horizontally.
 
Help proving this :
IMG_20190308_100451.jpeg
 

Attachments

  • IMG_20190308_100451.jpeg
    IMG_20190308_100451.jpeg
    22.7 KB · Views: 1,920
  • #10

Attachments

  • tapatalk_1552019845626.jpeg
    tapatalk_1552019845626.jpeg
    34.8 KB · Views: 1,527
  • #12
  • #13
Can't you simply separate the real and imaginary parts of the complex identity?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
  • · Replies 8 ·
Replies
8
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K