Proof Pascal's Law: Math Fluid Mech Homework Help

Click For Summary
SUMMARY

The discussion centers on the proof of Pascal's Law in Fluid Mechanics, specifically addressing the proof's reliance on the direction of pressure. The original poster (OP) expresses confusion over the necessity of demonstrating that pressure at a point M does not depend on the direction vector n. They propose a geometric approach using a prism to show equal pressures in different directions but question the need for multiple equalities to establish the proof. The conversation highlights the mathematical intricacies involved in understanding Pascal's Law and the challenges faced by those with a mathematical background rather than an engineering one.

PREREQUISITES
  • Understanding of Pascal's Law in Fluid Mechanics
  • Familiarity with vector mathematics and pressure concepts
  • Basic knowledge of geometric proofs
  • Experience with mathematical reasoning in physics contexts
NEXT STEPS
  • Research the derivation of Pascal's Law using geometric methods
  • Study vector calculus applications in fluid mechanics
  • Explore the relationship between pressure and direction in static fluids
  • Examine common mathematical proofs in engineering contexts
USEFUL FOR

Students of Fluid Mechanics, mathematicians seeking to understand physical applications, and educators looking for insights into teaching Pascal's Law effectively.

LFS
Messages
7
Reaction score
0

Homework Statement


My son was given a proof of Pascal's Law and told to learn it for his course in Fluid Mechanics.
a. It was done with a prism. I cannot type in a link, but google: pascal law prism and pick the first link and scroll down half a page to pressure and you will see this proof.
b. For the life of me, I cannot understand how this is possibly a proof since the direction of the pressure is NOT arbitrary.
c. So I attempted my own proof... However, I am a mathematician - not an engineer. I fixed the arbitrary direction problem. But I still do not understand something critical.

Homework Equations


I have posted my proof on scribd (remove the spaces):
scribd .com /doc /94146673

However, in my opinion my "proof" still has a mathematical flaw.

The Attempt at a Solution

Let M be a point in a static fluid and let p(n,M) be the pressure at a point M in the direction of an arbitrary vector n to M . Presumably - to prove Pascal's Law - I must show that p(n,M) does not depend on n.

Now, using the techniques of the prism proof, I "show" geometrically that p(n,M)=p(x,M)=p(y,M)=p(z,M) where p(x,M) is the pressure at point M in the direction of "positive x-axis", p(y,M) is the pressure at point M in the direction of positive y-axis, ...

Question: Mathematically, it seems to me that I need only ONE of these 3 equalities, e.g. p(n,M)=p(x,M). Using it, I could conclude that given another vector t to M p(t,M)=p(x,M) and conclude that p(t,M)=p(x,M)=p(n,M) and thus p(M) does not depend on my choice of vector.

I am certain that I need all 3 equalities, but WHY? Maybe something with the limits or even with the definition of p(n,M)?

Thanks for any help!
 
Physics news on Phys.org
Hello LFS, were you able to figure this out? I would love to know!
 
The original post is more than 3 years old, and the OP has not checked back in that time.

I think it's safe to say that you probably won't hear back from the OP.

PF also requests that you don't "necropost" to these older threads. It's perfectly fine for you to create your own thread if you have a question, and you can reference any other relevant threads.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
3K
Replies
2
Views
3K
  • · Replies 27 ·
Replies
27
Views
6K
Replies
6
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
10
Views
2K