Proof that In^-1=In | Linear Algebra

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Homework Help Overview

The discussion revolves around proving that the inverse of the identity matrix \( I_n \) is itself, denoted as \( I_n^{-1} = I_n \). This falls under the subject area of linear algebra, specifically focusing on properties of matrices and their inverses.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of an inverse matrix and question whether \( I_n \) serves as its own inverse. There are attempts to clarify the relationship between \( I_n \) and its inverse through definitions and properties.

Discussion Status

The discussion is ongoing, with participants affirming the relationship between \( I_n \) and its inverse. Some guidance is provided regarding the verification of the identity property, but no consensus has been reached on the proof itself.

Contextual Notes

Participants reference the definition of matrix inverses and the identity matrix, but there may be a lack of clarity on the formal proof structure or additional examples to support their claims.

cleopatra
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Homework Statement



In^-1=In
proof that!

Homework Equations


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0 1
= I2^-1= I2 for an example.
 
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The inverse matrix [tex]A^{-1}[/tex] of [tex]A[/tex] is by definition the matrix such that [tex]A^{-1}A=I_n[/tex] and [tex]AA^{-1}=I_n[/tex]. So is [tex]I_n[/tex] the inverse of [tex]I_n[/tex]?
 
yes In is the inverese of In because In^-1 is the inverse of In and In^-1=In
true?
 
anyone?
 
cleopatra said:
yes In is the inverese of In because In^-1 is the inverse of In and In^-1=In
true?

Just use the definition. You want to check that the inverse of [tex]I_n[/tex] is [tex]I_n[/tex] itself (this is just another way of saying [tex]I_n^{-1}=I_n[/tex]). What it comes down to is that [tex]I_nI_n=I_n[/tex].
 

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