MHB Proof That Radius of Melting Snowball Decreases Constantly

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A spherical snowball melts at a rate proportional to its surface area, leading to a decrease in volume that is directly related to this surface area. The relationship can be expressed mathematically with the equations for volume and surface area, where the volume V is given by V = (4/3)πr^3 and the surface area S by S = 4πr^2. By differentiating the volume with respect to time and equating it to the proportional surface area, it can be shown that the radius r decreases at a constant rate. This mathematical proof involves simplifying the differential equation derived from the volume and surface area relationships. Ultimately, the discussion confirms that the radius of the melting snowball decreases consistently over time.
markosheehan
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A spherical snowball is melting at a rate proportional to its surface area. That is, the rate at
which its volume is decreasing at any instant is proportional to its surface area at that instant.
(i) Prove that the radius of the snowball is decreasing at a constant rate.

can someone help me?
 
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markosheehan said:
A spherical snowball is melting at a rate proportional to its surface area. That is, the rate at
which its volume is decreasing at any instant is proportional to its surface area at that instant.
(i) Prove that the radius of the snowball is decreasing at a constant rate.

can someone help me?
Let V be the volume and S the surface area: dV/dt= kS for some constant k.
Now, You need to know that $V= \frac{4}{3}\pi r^3$ and $S= 4\pi r^2$.

So dV/dt= kS becomes $\frac{d(\frac{4}{3}\pi r^3)}{dr}= k(4\pi r^2)$.
Simplify the left side.
 

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