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Proof - Vector Calculus - Curl

  1. Mar 2, 2012 #1
    I need to prove this: u x ([itex]\nabla[/itex] x u) = [itex]\frac{1}{2}[/itex][itex]\nabla[/itex](u²) - (u [itex]\cdot[/itex] [itex]\nabla[/itex])u.

    I've came to this: uj∂iuj - uj∂jui (i think it's correct)
    But how this 1/2 appears?
  2. jcsd
  3. Mar 2, 2012 #2


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    welcome to pf!

    hi cristina89! welcome to pf! :smile:

    (try using the X2 button just above the Reply box :wink:)
    'cos ∂i(ujuj)= 2uji(uj) :wink:
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