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**Question:**

Let f: A -> B be a bijective function. Prove that

f o f^(-1) = IB

(IB = I lowercase B )

**Answer:**

Let x be an arbitrary element in the set A and f(x)=y . Therefore x is in A because f: A -> B.

f o f^(-1)

=f(f^(-1) (x))

and that's as far as i got

any help would be appreciated

thank you