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Proton and magnetic field question to see if i got the answers right?

  1. Oct 20, 2009 #1
    hey i just need to know if these answers are right i think i got it hopefully


    A proton of mass 1.67 x 10-27 kg is fired with a velocity of 1000 ms-1, into a uniform magnetic field of 2.00 T where the velocity and magnetic field are at right angles.

    (a) What is the magnitude and direction of the force acting on the proton?

    ok so the
    charge of a proton is +1.6x10^-19
    velocity = 1000
    the magnetic feild (B) = 2

    so it would be f=QVxB = 1.6x10^-19x1000x2= 3.2x10^-16
    F=3.2x10^-16
    still dont know how to find the direction of the force any help would be appreciated

    (b) What is the acceleration of the proton?
    A=f/m
    a=3.2x10^-16/1.67x10^-27=1.916167665x10^-43
    A=1.916167665x10^-43
     
  2. jcsd
  3. Oct 20, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    To find the direction of the force, use Flemming's left hand rule.
     
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