Can Two Protons Have the Same Speed After an Elastic Collision?

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In an elastic collision involving two protons of equal mass, the conservation of momentum and kinetic energy principles apply. The equations derived indicate that if one proton is initially at rest, the other will come to rest after the collision, while the initially stationary proton moves off at the same speed. It is concluded that both protons cannot have the same speed after the collision. The discussion raises uncertainty about the calculations and the correct approach to the problem. Ultimately, the consensus is that both protons cannot share the same speed post-collision.
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Homework Statement
1) A proton, moving with a velocity of v initial in the x direction collides elastically with another proton that is initially at rest. Assuming that the two protons have equal speeds after the collision, find (a) the speed of each proton after the collision in terms of v initial and
(b) the direction of the velocity vectors after the collision.
Relevant Equations
Equations for first problem:
m1v1i + m2v2i = (m1+m2)vf
v1i + v1f = v2i + v2f
and we know v1f = v2f
m2v2i = 0 since 2nd proton is initially at rest
mass of proton = (1.67 × 10^-27) kg
m1v1i + m2v2i = (m1+m2)vf
(1.67 × 10^-27)v1i = (1.67 × 10^-27 + 1.67 × 10^-27) vf
(1.67 × 10^-27/3.34 × 10^-27)v1i = (3.34 × 10^-27/3.34 × 10^-27) vf
(1.67 × 10^-27/3.34 × 10^-27)v1i = vf
(0.5)(v1i) = vf

not sure what to do from here nor if I'm in the correct path ?
 
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Hmm. About the question: an elastic collision between equal masses where one is initially at rest at the start will result in the other one coming to rest, and the one that was at initially rest moving off at the same speed. Is it possible for both to have the same speed after the collision? I don't think so...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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