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Proton deflection in a capacitor

  1. Feb 2, 2009 #1
    1. The problem statement, all variables and given/known data
    A proton traveling at a speed 1.0*106 m/s of enters the gap between the plates of a 2.0-cm-wide parallel-plate capacitor. The surface charge densities on the plates are 1*10^-6 C/m2.

    How far has the proton been deflected sideways when it reaches the far edge of the capacitor? Assume the electric field is uniform inside the capacitor and zero outside.


    2. Relevant equations
    d=.5at2


    3. The attempt at a solution
    1*10-4
     
  2. jcsd
  3. Feb 2, 2009 #2

    berkeman

    User Avatar

    Staff: Mentor

    Thread moved to Intro Physics.

    Welcome to the PF, badBKO. Could you please show us more of your work, including units? What force creates the sideways acceleration? How do you calculate the magnitude of that force?
     
  4. Feb 2, 2009 #3
    The force that moved it to the right is not needed. There is no acceleration in the x deminsion, on lay in the y. The ending answer should be in millimeters of displacement.


    I tried using kinematics in 2 dimension x and y
    x1, y1, t1, etc

    and the equations

    y1 = y0 + vy(t1-t0) + .5ay(t1-t0)2

    used the same equation for the x variable also.
     
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