Proton hits infinite charged plane, find charge of plane

  • Thread starter aliaze1
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  • #1
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Homework Statement



An electron is released from rest 2.0 cm from an infinite charged plane. It accelerates toward the plane and collides with a speed of 1*107 m/s

What is the surface charge density of the plane?


Homework Equations



a=(qE)/m
v=v0+a∆t

The Attempt at a Solution



v0=0
therefore a∆t = 1*107 m/s
∆t=L/v0

calculating the time ∆t requires knowledge of either v0 or a, v0 is zero, so one cannot calculate it using v0, so the other option is to use a, which is unknown also

How would I go about this?

Once I have a, i can find E using the formula a=(qE)/m

Thanks
 
Last edited:

Answers and Replies

  • #2
The electric field intensity of an infinite charged plate is given by-

E=S/2E0

E0=8.854*10 powered to -12 S is the surface charge density.

substitue the above formula as the E for the the a=(qE)/m then proceed as planned.

report if your work was done
 

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