Proton hits infinite charged plane, find charge of plane

[aliaze1]

Homework Statement

An electron is released from rest 2.0 cm from an infinite charged plane. It accelerates toward the plane and collides with a speed of 1*10⁷ m/s

What is the surface charge density of the plane?

Homework Equations

a=(qE)/m
v=v₀+a∆t

The Attempt at a Solution

v₀=0
therefore a∆t = 1*10⁷ m/s
∆t=L/v₀

calculating the time ∆t requires knowledge of either v₀ or a, v₀ is zero, so one cannot calculate it using v₀, so the other option is to use a, which is unknown also

How would I go about this?

Once I have a, i can find E using the formula a=(qE)/m

Thanks

 

[mishraanwesh]

The electric field intensity of an infinite charged plate is given by-

E=S/2E0

E0=8.854*10 powered to -12 S is the surface charge density.

substitue the above formula as the E for the the a=(qE)/m then proceed as planned.

report if your work was done