Prove 2-Norm: A*A = A^2 Math Help

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How do you prove that

[tex]\left\|A^{*} A \right\|_{2}= \left\| A \right\|^{2}_{2}[/tex] ?

I can prove that [tex]\left\|A^{*} A \right\|_{2} \leq \left\| A \right\|^{2}_{2}[/tex]

but I am not sure how to do it for the other inequality.
 
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I am sorry, let me specify: [tex]A \in \textbf{C}^{m\times n}[/tex] and [tex]A^{*}[/tex] is the conjugate transpose of A.

Is it true that [tex]\left\| A^{*}A \right\|_{2} \geq \left\| A \right\|^{2}_{2}[/tex] ?

If yes, how do you prove this
 


math8 said:
How do you prove that

[tex]\left\|A^{*} A \right\|_{2}= \left\| A \right\|^{2}_{2}[/tex] ?

I can prove that [tex]\left\|A^{*} A \right\|_{2} \leq \left\| A \right\|^{2}_{2}[/tex]

but I am not sure how to do it for the other inequality.

Try it with

A = [[1,2],[3,4]]

Edit: Better yet, try the identity matrix.
 
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