- #1
Hernaner28
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- 0
Using the inequalities: [tex]\sin x \leq x \leq \tan x[/tex] valid in a zero range, prove that:
[tex]\displaystyle\lim_{x \to{0}}{\frac{x}{\sin x}}= 1[/tex]
Thank you!
[tex]\displaystyle\lim_{x \to{0}}{\frac{x}{\sin x}}= 1[/tex]
Thank you!