Prove an odd function is strictly increasing

[xsw001]

f:R->R is odd, if f(-x)=-f(x) for all x
Show if f:R->R is odd and the restriction of this function to the interval [0, infinity) is strictly increasing
Then f:R->R itself is strictly increasing

I’m very confused about what the question is exactly asking for. From my understanding of the question is that I have any odd function and the graph is strictly increasing in the first quadratic . I need to prove entire graph of such odd function is strictly increasing? Am I interpreting it correctly?
I know how to prove for a strictly increasing function. Let u, v in R, find f(v)-f(u)>0, then f:R->R is strictly increasing function.

Proof:
Given f is an odd function and f is strictly increasing in [0, infinity)
Then f(D) = I, the image of the function is an interval
Therefore f is continuous and strictly increasing?

 

[fzero]

Just examine the behavior of the function on the interval $$(-\infty, 0)$$.

 

[xsw001]

Okay, got it!