Prove Determinant of Rotation Matrix is 1 w/Continuity Argument

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The discussion centers on proving that the determinant of a rotation matrix is always 1, with some participants expressing confusion about the concept of a continuity argument in this context. A straightforward method to demonstrate this involves calculating the determinant of a specific rotation matrix, such as the one for a clockwise rotation about the z-axis. Additionally, Euler's rotation theorem is mentioned, indicating that any rotation matrix can be expressed as a product of rotation matrices around the three axes, reinforcing that their determinants multiply to 1. The conversation also touches on definitions of rotation matrices, emphasizing their properties as isometric and orientation-preserving transformations. Ultimately, the conclusion is that rotation matrices can be represented in a form that guarantees their determinant is 1.
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What's a continuity argument? For example, a question asks to prove that the determinant of a rotation matrix is always 1 using a continuity argument?
 
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Anyone? How would i prove in general that the det of a rotation matrix is 1?
 
I am unsure of what you mean by a continuity argument as it pertains to matrices and determinants. But you can straightforwardly show that the determinant of a rotation matrix is 1 by writing down the matrix and taking its determinant.

For instance, a clockwise rotation by an angle \theta about the z axis is described by the following matrix:

R_z(\theta)=\left[\begin{array}{ccc}\cos(\theta)&sin(\theta)&0 \\ -\sin(\theta)&\cos(\theta)&0 \\ 0&0&1 \end{array}\right ]

It's a piece of cake to show that det(R_z(\theta))=1.
 
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I'm not sure what the question means by continuity argument either. That's why I asked.

I know could just take the determinant of the rotation matrix. Since by euler's rotation theorem any rotation matrix M can be expressed as rotations over three perpendicular axis, det M = det R1 * det R2 * det R3 = 1, where R1, R2, and R3, are just the general rotation matrices for rotating over x,y, and z axis. But I wasn't sure if this 'proof' is sufficiently rigorous and general.
 
When asking questions like this one it would be nice to define what you are talking about. In this case a rotation matrix. The definition
Rotation matrix: A matrix for which det(A)=1
would be very helpful

Another definition is
Rotation matrix: An isometric orientation preserving linear transform
by isometric I mean the inner product defined by A matches the one defined by I (idenity matrix)
(Ax)'Ay=x'y
where ' is the adjoint (conjugate transpose or if A is real transpose)
immediately we have
A'A=I
This only insures abs(det(A))=1
so we turn to the orientation preserving bit
That is fancy talk, but it means that I is our prototype rotation
that is
T(x,y,z)=(-x,y,z)
would be a "bad" or improper rotation
we want for A a rotation and B any matrix
det(AB)=det(B)
which again does not teach us much
I said we want I to be a prototype
det(I)=1 but again we want to go further
say h is a small number and we wish to construct an almost rotation
I+Ah
we have
(I+Ah)'=I+A'h
and
(I+Ah)^-1~I-Ah
thus we require
A'=-A
we could also make better almost rotations
I+Ah+A^2h^2/2+A^3h^3/6+...
The ultimate result being the actual rotation
exp(Ah)
and
of course
A'=-A->tr(A)=0
det(exp(At))=exp(tr(At))=exp(0)=1
Thus rotation matricies are of the form exp(A) where A'=-A thus have det=1
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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