Prove/Disprove: Existence of a Basis of P_3(F) w/ Degree 2 Polynomial

Click For Summary

Homework Help Overview

The discussion revolves around the existence of a basis for the vector space of polynomials of degree at most 3, denoted as P_3(F), specifically addressing whether one of the basis polynomials can have a degree of 2.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the validity of a proposed proof regarding the basis elements and their degrees, questioning the sufficiency of the argument presented. There is also a suggestion to consider a matrix representation related to the basis.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's proof attempt. Some clarification on the original problem statement has been made, and there is an ongoing examination of the implications of the proof's assumptions.

Contextual Notes

Participants note a potential typo in the original problem statement regarding the degree of the polynomials, which may affect the interpretation of the proof.

jaejoon89
Messages
187
Reaction score
0

Homework Statement



Prove or disprove: there exists a basis (p_0, p_1, p_2, p_3) of P_3 (F) such that one of the polynomials p_0, p_1, p_2, p_3 has degree 2.

Homework Equations



none really

The Attempt at a Solution



Is the following proof correct?

----

Let p_0, p_1, p_2, p_3 be elements of P_3(F) s.t.

p_o (x) = 1,
p_1 (x) = x,
p_2 (x) = x^2 + x^3,
p_3(x) = x^3.

None of the polynomials are degree 2 although (p_0,p_1,p_2,p_3) is clearly spanning P_3 (F) with dimP_3(F) = 4 and forms a basis. Hence proved.
 
Physics news on Phys.org
Looks good to me assuming the "one" in the statement of the problem should be "none".
 
I'm not sure that stating that it clearly spans it will suffice even if it is obvious. If you think that this suffices for you class, you're fine.

On the other hand, you could cook up a matrix that maps a degree three polynomial represented in the standard basis to it's representation in this basis pretty easily.
 
Typo: the original statement is supposed to be "none of the polynomials has degree 2." Thanks for pointing that out, LCKurtz.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
1
Views
2K
Replies
8
Views
2K