MHB Prove/Disprove: Uniform Continuity of sin(sin(x))

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The discussion centers on proving or disproving the uniform continuity of the function sin(sin(x)) using the ε, δ definition. Participants clarify the ε, δ definition, which states that for every ε > 0, there exists a δ > 0 such that if |x - y| < δ, then |f(x) - f(y)| < ε for all x, y in the domain. A hint is provided using the formula sin(x) - sin(y) = 2cos((x+y)/2)sin((x-y)/2) to assist in the proof. The challenge invites participants to explore the uniform continuity of the nested sine function. The conversation emphasizes understanding the ε, δ definition as a foundational concept in real analysis.
solakis1
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prove or disprove if the following function is uniformly continuous:

$$sin(sin(x)) $$ using the ε,δ definition
 
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Do you know what that means? What IS the "$\epsilon, \delta$ definition"?
 
Country Boy said:
Do you know what that means? What IS the "$\epsilon, \delta$ definition"?
This is a challenge problem. solaklis wants you to find the answer...

-Dan
 
hint
[sp]Use the formula :
sinx-siny =$2cos\frac{x+y}{2}sin\frac{x-y}{2}$[/sp]
 
Country Boy said:
Do you know what that means? What IS the "$\epsilon, \delta$ definition"?
The $\epsilon$ $\delta$ definition for real function f(x) is :

Given $\epsilon>0$ there exists a $\delta>0$ such that :
For all x,y belonging the to domain of f(x) and $|x-y|<\delta$ then $|f(x)-f(y)|<\epsilon$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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