Prove g'(x)=g(x): Hints & Solutions

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Homework Help Overview

The problem involves two functions, f and g, defined on the real numbers, with specific properties that relate them. The goal is to prove that the derivative of g, denoted g'(x), is equal to g(x) for all x. The discussion revolves around the implications of the given properties of g and the limit definition of the derivative.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the limit definition of the derivative and its application to the function g. There are questions about how to manipulate the expression for the derivative using the properties of g. Some participants suggest focusing on the limit as h approaches 0.

Discussion Status

Participants are actively engaging with the problem, with some providing hints and affirmations regarding the use of the limit definition. There is a recognition of the importance of the properties of g in the derivation process, and some participants express confidence in the approach being taken.

Contextual Notes

There is an emphasis on the three properties of g that must be considered while applying the limit definition of the derivative. The original poster expresses uncertainty about how to start the problem, indicating a need for guidance in understanding the implications of the properties provided.

drawar
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Homework Statement


Let f and g be two functions on ℝ such that:
1. g(x) = xf(x) + 1 for all x,
2. g(x + y) = g(x)g(y) for all x,y,
3. \mathop {\lim }\limits_{x \to 0} f(x) = 1.
Prove that: g'(x) = g(x) for all x.

Homework Equations


The Attempt at a Solution


Sorry for asking this question without showing my workings but I just don't know how to get started. Any hints would be much appreciated. TIA!
 
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drawar said:

Homework Statement


Let f and g be two functions on ℝ such that:
1. g(x) = xf(x) + 1 for all x,
2. g(x + y) = g(x)g(y) for all x,y,
3. \mathop {\lim }\limits_{x \to 0} f(x) = 1.
Prove that: g'(x) = g(x) for all x.

Homework Equations



The Attempt at a Solution


Sorry for asking this question without showing my workings but I just don't know how to get started. Any hints would be much appreciated. TIA!
Just use the "limit" definition of the derivative.
 
SammyS said:
Just use the "limit" definition of the derivative.

So I have to prove \mathop {\lim }\limits_{h \to 0} \frac{{g(x + h) - g(x)}}{h} = g(x)?
 
drawar said:
So I have to prove \mathop {\lim }\limits_{h \to 0} \frac{{g(x + h) - g(x)}}{h} = g(x)?

Yes.

It works out quite nicely.
 
SammyS said:
Yes.

It works out quite nicely.

Yup, remember the 3 properties while you use the precise definition of derivative.
 
Thank you all, please check my working below:

g'(x) = \mathop {\lim }\limits_{h \to 0} \frac{{g(x + h) - g(x)}}{h} = \mathop {\lim }\limits_{h \to 0} \frac{{g(x).g(h) - g(x)}}{h} = \mathop {\lim }\limits_{h \to 0} \frac{{g(x).((g(h) - 1)}}{h} = \mathop {\lim }\limits_{h \to 0} \frac{{g(x)hf(h)}}{h} = \mathop {\lim }\limits_{h \to 0} g(x)f(h) = \mathop {\lim }\limits_{h \to 0} g(x).\mathop {\lim }\limits_{h \to 0} f(h) = \mathop {\lim }\limits_{h \to 0} g(x) = g(x)
 
That looks correct to me.
 

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