Prove \mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+} is Countable

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Homework Statement


Prove that [tex]\mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+}[/tex] is countable, where X is the Cartesian product.

Homework Equations


The Attempt at a Solution


I'm lost as to where to start proving this.
 
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The Captain said:

Homework Statement


Prove that [tex]\mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+}[/tex] is countable, where X is the Cartesian product.


Homework Equations





The Attempt at a Solution


I'm lost as to where to start proving this.

do you know how to prove this

[tex]\mathbb Z^{+} X \: \mathbb Z^{+}[/tex]

is countable?
 
There are many ways to do this you show that there it bijection from N to ZxZ ,that is , ZxZ is countable. Then show that there is bijection from ZxZ to ZxZxZ.

EDIT
someone beat me to it.
 
I had to prove that [tex]\mathbb Z^{+} \: X \: Z^{+} \: \rightarrow \: Z^{+}[/tex] was one-one and onto using [tex]f(a,b)=2^{a-1}(2b-1)[/tex], does that count for proving it's countable, and if it's not, no I don't know how to prove it's countable.

The class I'm taking is a giant leap from Calc 4, and Abstract Algebra isn't even pre-req though it probably should be because the professor keeps asking who's taking it before.
 
Yes, that is a bijection. So you have already shown the first part all you need to do provide a bijection from ZxZxZ to ZxZ .