Prove Maxwell Eqs. Covariant: Wave Eqn & 4th-Vector Pot.

  • Context: Graduate 
  • Thread starter Thread starter martindrech
  • Start date Start date
  • Tags Tags
    Covariant Maxwell
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
martindrech
Messages
4
Reaction score
0
Is it enough to see the covariance of the wave equation the fourth-vector potential ([itex]\phi[/itex], [itex]\bar{A}[/itex]) satisfy? I mean, is this enough to prove the covariance of Maxwell equations?

The equation would be [itex]∂_{\mu}[/itex][itex]∂^{\mu}[/itex][itex]A^{\nu}[/itex]=[itex]\frac{4\pi}{c}[/itex] [itex]J^{\nu}[/itex]

[itex][/itex]
 
Physics news on Phys.org
Why can't you just look at Maxwell's equations directly to see that they are covariant?

[tex]\partial_{\mu} F^{\nu \rho} + \partial_{\nu} F^{\rho \mu} + \partial^{\rho} F^{\mu \nu} = 0[/tex]

[tex]\nabla_{\mu} F^{\mu \nu} = 4 \pi J^{\nu}[/tex]
 
Simply because is easier to look (using fourth-vectors) at the equations for the potentials instead of the equation for the fields.
 
martindrech said:
Simply because is easier to look (using fourth-vectors) at the equations for the potentials instead of the equation for the fields.

If the two equations are logically equivalent, yes, you could look at either one. But I don't think the wave equation for the 4-potential is logically equivalent to Maxwell's Equations; Maxwell's Equations imply the wave equation, but I'm not sure the converse is true.