Prove: Non-constant Polynomials as Products of Irreducibles

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SUMMARY

Every non-constant polynomial over a field F can be expressed as a product of irreducible polynomials. This conclusion is supported by the definition of irreducibility, where a polynomial is irreducible if it cannot be factored into the product of two non-constant polynomials. For instance, the polynomial x² - a² can be factored into (x - a)(x + a), demonstrating that it is a product of two first-degree irreducible polynomials. The degree of the irreducible factors must sum to the degree of the original polynomial.

PREREQUISITES
  • Understanding of polynomial definitions and properties
  • Knowledge of irreducible and reducible polynomials
  • Familiarity with polynomial degree concepts
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the definitions and examples of irreducible polynomials in field theory
  • Learn about polynomial factorization techniques over various fields
  • Explore the Fundamental Theorem of Algebra and its implications for polynomial roots
  • Investigate the role of unique factorization domains in polynomial rings
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Mathematics students, algebra enthusiasts, and educators looking to deepen their understanding of polynomial factorization and irreducibility concepts.

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Homework Statement


For polynomials over a field F, prove that every non constant polynomial can be expressed as a product of irreducible polynomial.


Homework Equations


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The Attempt at a Solution


Well a hint the teacher gave me was that the degree of the irreducible polynomial
has to be the same as the original polynomial.
 
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Surely you misunderstood. I have no idea what you mean by "the irreducible polynomial" since you are talking about a product of such things and there will generally be more than one. Also the total degree must be equal to the pdegree of the original polynomial. For example x2- a2= (x- a)(x+ a) is a second degree polynomial that is the product of two first degree irreducible polynomials.

Start with the definitions of "reducible" and "irreducible".
 

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