Prove or disprove: Is 10^1,000 - 9 Prime?

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Homework Help Overview

The discussion revolves around the question of whether the expression 10^1,000 - 9 is a prime number. Participants are exploring the properties of large numbers and prime determination within the context of number theory.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to analyze the expression by considering the form of 10^1,000 and its relation to perfect squares. There is discussion about dropping leading digits and focusing on smaller components like 91. Some participants question the implications of the difference of two squares and its relation to primality.

Discussion Status

The conversation is ongoing, with participants sharing insights about the properties of prime numbers and the structure of the expression. There is a mix of attempts to reason through the problem and clarifications about mathematical concepts, but no consensus has been reached.

Contextual Notes

Participants are grappling with the implications of the difference of two squares and how it relates to primality, while also noting specific examples that illustrate their points. The discussion reflects a range of interpretations and approaches to the problem.

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Homework Statement



Prove or disprove: Is 10^1,000 - 9 Prime?


Homework Equations





The Attempt at a Solution



10^1,000 = 999...91.

Is there a way to logically argue to drop the first nine hundred ninety eight 9's and just look at 91 as being a prime?
 
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srfriggen said:

Homework Statement



Prove or disprove: Is 10^1,000 - 9 Prime?


Homework Equations





The Attempt at a Solution



10^1,000 = 999...91.

Is there a way to logically argue to drop the first nine hundred ninety eight 9's and just look at 91 as being a prime?
No.
Notice that 101000 is a perfect square, and so is 9.
 
You would think that might work.
However:
91 is prime
991 is prime
9991 = 103*97, but both of these are prime factors
99991 is prime
999991 = ?
 
Mark44 said:
No.
Notice that 101000 is a perfect square, and so is 9.

But the difference between two perfect squares isn't always prime. For example, 25-16=9.

Not following the logic yet :/
 
srfriggen said:
But the difference between two perfect squares isn't always prime. For example, 25-16=9.

Not following the logic yet :/

What can you do with the difference of two squares?
 
srfriggen said:
But the difference between two perfect squares isn't always prime. For example, 25-16=9.

Not following the logic yet :/

That's why he answered "No" to the question of whether it's prime!
 
Mark44 said:
What can you do with the difference of two squares?

LOL he gave away the answer then!

I've gotten to this point now: "Call 10^1,000 x^2 and 9=3^2. x2-32=(x+3)(x-3)."

Thinking a proof by contradiction technique may work but mulling it over I can't see how (x+3)(x-3)=p, where p is prime, would lead to a contradiction. If I'm on the right path let me know and I'll try to work it out some more.
 
srfriggen said:
LOL he gave away the answer then!

I've gotten to this point now: "Call 10^1,000 x^2 and 9=3^2. x2-32=(x+3)(x-3)."

Thinking a proof by contradiction technique may work but mulling it over I can't see how (x+3)(x-3)=p, where p is prime, would lead to a contradiction. If I'm on the right path let me know and I'll try to work it out some more.

You should just start writing down what you know about prime numbers, you should write down the relevant point fairly quickly.
 
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Office_Shredder said:
You should just start writing down what you know about prime numbers, you should write down the relevant point fairly quickly.

"...(x+3)(x-3)=N, and N is divisible by (x+3) OR (x-3). It cannot be prime since a prime is only divisible by itself and the number 1."

that work?
 
  • #10
That sounds reasonable, except I'm not sure why you use the word OR when describing what N is divisible why... and would be more appropriate.
 
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