Tsunoyukami said:
Thanks! I'm familiar with these concepts and I'm not sure why I didn't think of them in the first place!
Is there another simple explanation one could offer when explaining this idea to students unfamiliar with linear algebra? I've been asked about this concept by several friends taking high school level physics and, though the notions of linear independence and basis are not overtly difficult, they do require some knowledge of linear algebra that goes what might be called "significantly" beyond the high school curriculum. (For example, I personally learned of the independence of x- and y- components in Grade 11 (10, maybe?) and learned about linear independence and basis in my first real algebra class two (three?) years later while at university.)
Thanks again!
If, you can write the equations of motion so that the x-terms (v_x, a_x, x) only "talk" to each other, and the same goes for the y and z terms, then there is no way for what is happening with y to effect x or z.
I.e.
F_x = k_x * x
F_y = k_y * y - g * v_y
F_z = 0
Th force in the y direction only changes what is going on in the y direction, and vice versa for the x direction. To understand the motion in the x direction, you need to only solve the first equation. To solve for the motion in the y direction, you need only solve the second equation.
If, on the other hand, you had a situation where the forces look like:
F_x = k*x - g* v_y
F_y = n*y
You now have a "mixing" term in the first equation, where what is going on in y effects what is happening in x. I.e. you cannot say what will be going on with x, until you know what is going on with y -- the equations are coupled.
This is a common occurrence (coupled differential equations) in physics. You will see this a lot in quantum mechanics (time-dependent perturbation theory, particle scattering), except in qm, the coupled equations are not "equations of motion".