How can we prove the derivative of tan(y/2) is 2/(1 + x²)?

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The discussion focuses on proving the derivative of the function tan(y/2) with respect to x, specifically demonstrating that dy/dx equals 2/(1 + x²). The user references the Pythagorean identity tan²(x) + 1 = sec²(x) to establish a relationship between the functions. The key step involves differentiating both sides of the equation x = tan(y/2) to derive the required result. The original question can be found in the Edexcel GCE Pure Maths C1 C4 Specimen Paper.

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thomas49th
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Prove:

\frac{Sec^{2}\frac{y}{2}}{2} \eqiv \frac{2}{1+x^{2}}

Well i know from the pythagorean identities that tan^{2}x + 1 = sec^{2}x
so

\frac{tan^{2}\frac{y}{2} + 1}{2} \eqiv \frac{2}{1+x^{2}}

But now I am stuck!

If your interested the full qusetion is page 35, question 7 (ii) here:

http://www.edexcel.org.uk/VirtualContent/105484/GCE_Pure_Maths_C1_C4_Specimen_Paper_MkScheme.pdf

Can someone point me in the right direction

Cheerz
 
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The actual question is:

Given that x = tan(y/2), prove that dy/dx = 2/(1 + x²).​

thomas49th, just differentiate both sides of x = tan(y/2). :smile:
 

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