Prove that diagonal matrices are symmetric matrices

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A diagonal matrix is defined by the property that its off-diagonal elements are zero, leading to the conclusion that for all indices i and j, A_{ij} = A_{ji}. This property directly implies that the transpose of the matrix, A^t, equals the original matrix, A, confirming that diagonal matrices are symmetric. The discussion raises a question about the necessity of proving the initial property for diagonal matrices, but it is asserted that no further proof is needed since the defining characteristics inherently support the symmetry. Overall, the argument presented effectively demonstrates that diagonal matrices are indeed symmetric. The proof is considered valid without requiring additional justification.
Mr Davis 97
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Homework Statement


Same as title.

Homework Equations

The Attempt at a Solution


A defining property of a diagonal matrix is that ##A_{ij} = A_{ji} ~~\forall i,j \le n##. This means that ##((A)^{t})_{ji} = A_{ji}##. Therefore, we know that ##A^t = A##. This shows that a diagonal matrix is symmetric.

Is this an okay proof? Am I making too big of a leap in logic to start with ##A_{ij} = A_{ji} ~~\forall i,j \le n##? Or do I need to first prove that that statement is true for diagonal matrices?
 
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I would say, in the case of a diagonal matrix, there is nothing to prove, since all ##A_{ij} = 0 = A_{ji}## for ##i \neq j## and of course is ##A_{ii}=A_{ii}## for the rest.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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