Prove that dirichlet function is periodic

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SUMMARY

The Dirichlet function, defined as the characteristic function of the rationals, is proven to be periodic with a period of 1. This is established by demonstrating that if \(x\) is rational, then \(x + 1\) remains rational, and similarly, if \(x\) is irrational, then \(x + 1\) is also irrational. The discussion raises the question of whether there exists a fundamental period smaller than 1 and suggests further exploration into the function's continuity and Riemann integrability, highlighting its nowhere continuous nature.

PREREQUISITES
  • Understanding of the Dirichlet function and its definition
  • Knowledge of rational and irrational numbers
  • Familiarity with periodic functions and their properties
  • Basic concepts of continuity and Riemann integrability
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  • Investigate the properties of periodic functions with different periods
  • Explore the implications of the Dirichlet function being nowhere continuous
  • Study the concept of Riemann integrability and its relation to continuous functions
  • Examine functions that are periodic with arbitrarily small periods
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Mathematicians, students studying real analysis, and anyone interested in the properties of periodic functions and their implications in calculus.

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Hey,

I need to prove that dirichlet function is a periodic function,
but i got no idea how to start solving the question.
could anyone help please?
 
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Do you mean the characteristic function of the rationals,
\[
f(x) =
\begin{cases}
1& (x \in \mathbb{Q})\\
0& (x \not\in \mathbb{Q})
\end{cases}
\]
?
 
Krylov said:
Do you mean the characteristic function of the rationals,
\[
f(x) =
\begin{cases}
1& (x \in \mathbb{Q})\\
0& (x \not\in \mathbb{Q})
\end{cases}
\]
?

yes
 
Can you prove that if $x$ is rational, then $x + 1$ is rational?
Can you prove that if $x$ is irrational, then $x + 1$ is irrational?
 
That would be sufficient to show that f is "periodic with period 1". Is there a "fundamental" (smallest positive) period?
 
What about a rational constant, say $c$, in the place of $1$?
 
greg1313 said:
What about a rational constant, say $c$, in the place of $1$?

That would have been my next question...

HallsofIvy said:
That would be sufficient to show that f is "periodic with period 1". Is there a "fundamental" (smallest positive) period?

...and that the question after that (Nod)

I hope the OP still comes back. This function provides a nice exercise. Once the above is done, he could try to go on by proving (without looking it up somewhere) that this function is nowhere continuous, hence not Riemann integrable over any compact interval.

On the other hand, he could also investigate what a continuous function looks like when it is periodic with arbitrarily small periods.
 

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