Prove that if L is regular, then L^R is regular

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SUMMARY

If a language L is regular, then its reverse L^R is also regular. This can be proven by constructing a regular expression r that generates L and recursively building an expression for L^R. Alternatively, one can take a Deterministic Finite Automaton (DFA) that accepts L, reverse all transitions, and add a new initial state with ε-transitions to all original accepting states.

PREREQUISITES
  • Understanding of regular languages and their properties
  • Familiarity with regular expressions and their construction
  • Knowledge of Deterministic Finite Automata (DFA)
  • Concept of ε-transitions in automata theory
NEXT STEPS
  • Study the construction of regular expressions for various languages
  • Learn about the properties of Deterministic Finite Automata (DFA)
  • Explore the concept of language reversal and its implications
  • Investigate ε-transitions and their role in automata theory
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The discussion is beneficial for computer science students, automata theorists, and anyone interested in formal language theory and the properties of regular languages.

Julio1
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Prove that if $L$ is regular, then $L^R=\{w^R, w\in L\}$ is regular.

Hello MHB! I need if you can help me with this problem. Thank you.
 
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One way is to take a regular expression $r$ that generates $L$ and construct an expression that generates $L^R$. It is built by recursion on $r$.

Another way is to take a DFA accepting $L$ and reverse all arrows. One also has to add a new initial state and add $\varepsilon$-transitions from it to all old accepting states.
 

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