Prove that similar matrices have the same rank

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Similar matrices are defined by the equation B = P^(-1)AP, where P is an invertible matrix. Since the rank of an invertible matrix P is equal to n, it does not alter the rank of matrix A during multiplication. Therefore, the ranks of matrices A and B are equal, establishing that similar matrices have the same rank. Additionally, proving that rank(P^(-1)AP) is less than or equal to rank(A) suffices, as matrix similarity is symmetric. This confirms that if A is similar to B, then B is also similar to A, reinforcing the conclusion.
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Homework Statement



Prove that similar matrices have the same rank.


Homework Equations





The Attempt at a Solution



Similar matrices are related via: B = P-1AP, where B, A and P are nxn matrices..
since P is invertible, it rank(P) = n, and so since the main diagonal of P all > 0, multiplying by P will not change the rank of A, so rank B = rank A.

Is that seem right?
 
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If you can show that rank(P-1AP) is less than or equal to rank(A), then you are done since matrix similarity is symmetric (if A is similar to B, then B is similar to A).
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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