Prove that the standard basis vectors span R^2

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R^2 is considered a vector space over the field R because it allows for a complete basis using the standard basis vectors e_1 and e_2. When considering R^2 over the field Q, complications arise as a basis would require an uncountably infinite set, which is not feasible without the axiom of choice. This distinction is crucial because it highlights the limitations of using different fields for vector spaces. The standard basis vectors effectively span R^2, demonstrating that any vector in this space can be expressed as a linear combination of e_1 and e_2. Understanding the field over which a vector space is defined is essential for proper mathematical formulation.
Mathematicsresear
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Homework Statement


I know how to approach this problem; however, I'm just confused as to why we consider that R^2 is a vector space over the field R, and not Q or any other field for this question?

Standard basis vectors: e_1, e_2 or i,j
 
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Mathematicsresear said:

Homework Statement


I know how to approach this problem; however, I'm just confused as to why we consider that R^2 is a vector space over the field R, and not Q or any other field for this question?

Standard basis vectors: e_1, e_2 or i,j

You will have difficulty writing down a basis of ##\mathbb{R}^2## over the field ##\mathbb{Q}##: such a basis is uncountably infinite and you need the axiom of choice to show it exists.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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