Prove the shortest distance between two points is a line

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The discussion focuses on proving that the shortest distance between two points is a straight line segment. It begins with the definition of an arclength parametrized curve, stating that the distance between the endpoints cannot exceed L, the length of the curve. The key argument is that equality holds only when the curve is a straight line. The attempt to solve this includes using the properties of arclength and suggests that the calculus of variations may provide a method for proving the equality condition. The conclusion emphasizes that understanding these concepts is essential for demonstrating the shortest path theorem.
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Homework Statement



Let γ : [0, L] → Rn be arclength parametrized. Show that the distance between the endpoints of the curve can at most be L, and equality can only hold when γ is a straight line segment. Thus, the shortest path between two points is the straight line segment connecting them.

Homework Equations



I guess maybe arclength: s(t) = ∫ ||γ'(t')||dt' from 0 to t

The Attempt at a Solution


So my attempt would be to include the properties of an arclength parameterized curve; Namely that the length of such a curve is 1. Such that when you compute the arc length you get something like ∫1dt' from 0 to t (or in this specific case 0 to L) this tells us the length is L but I don't know how to prove that the equality holds only when its a straight line. Any suggestions?
 
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*cough* Calculus of variations *cough*
 
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Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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