# Prove this inequality with binomial

## Homework Statement

Prove that

$\sum_{k=0}^n {3k\choose k}\ge \frac{5^n-1}{4}$

## Homework Equations

${3k\choose k}= \frac{(3k)!}{k!(2k)!}$

## The Attempt at a Solution

I tried using the induction principle, but...

Here my attempt:

For $n=0$ 1>0 ok

Suppose that is true for $n$, i.e.:

$\sum_{k=0}^n {3k\choose k}\ge \frac{5^n-1}{4}$

Now:

$\sum_{k=0}^{n+1} {3k\choose k}= \sum_{k=0}^{n} {3k\choose k}+ {3(n+1)\choose (n+1)}\ge \frac{5^n-1}{4}+{3(n+1)\choose (n+1)}$

But now I don't know what to do, maybe it is not the correct way to show this... I need your help