Provide an example or prove it wrong

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The discussion centers on the existence of a continuous function g: Q --> R that satisfies g(0)=0 and g(1)=1, while ensuring there is no x in Q such that g(x)=1/2. The proposed function f(x) = x^2 meets the criteria, as it correctly evaluates to f(0)=0 and f(1)=1. The conclusion drawn is that since f(x) = 1/2 requires an irrational x, the existence of such a continuous function is validated without the need for further proof.

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Homework Statement


A continuous function g: Q --> R such that g(0)=0 and g(1)=1, but there does not exist any x in Q such that g(x)=1/2

Homework Equations


Number sets, basic number theory

The Attempt at a Solution


The function could be [tex]f(x) = x^2[/tex]

since

[tex]f(0) = 0[/tex]

[tex]f(1) = 1[/tex]

[tex]f(x) = 1/2[/tex]

here it looks like [tex]x[/tex] must be an irrational. One could refer to the demonstration that the diagonal of a square is an irrational.

Is it enough as a prove ?
 
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Quinzio said:

Homework Statement


A continuous function g: Q --> R such that g(0)=0 and g(1)=1, but there does not exist any x in Q such that g(x)=1/2


Homework Equations


Number sets, basic number theory



The Attempt at a Solution


The function could be [tex]f(x) = x^2[/tex]

since

[tex]f(0) = 0[/tex]

[tex]f(1) = 1[/tex]

[tex]f(x) = 1/2[/tex]

here it looks like [tex]x[/tex] must be an irrational. One could refer to the demonstration that the diagonal of a square is an irrational.

Is it enough as a prove ?

Going by the title of your thread, you need to do one of two things:
1) Provide an example for which the conditions are met.
2) Prove that no such example exists.

f(x) = x2 is an example that works, so you don't need to prove anything.
 
Mark44 said:
Going by the title of your thread, you need to do one of two things:
1) Provide an example for which the conditions are met.
2) Prove that no such example exists.

f(x) = x2 is an example that works, so you don't need to prove anything.

Ok, I see.

Thanks for your contributions.
 

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