Proving a Limit Using Delta-Epsilon Definition

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Homework Help Overview

The original poster is attempting to prove the limit of the arctangent function as x approaches infinity using the delta-epsilon definition. The specific limit in question is \lim_{x\rightarrow \infty} \arctan(x)=\frac{\pi}{2}. There is a noted lack of experience with trigonometric functions in the context of this proof.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the necessity of using the delta-epsilon definition and suggest alternative perspectives, such as considering the graph of the arctangent function. There are suggestions to solve the inequality | \arctan x - \pi / 2 | < \epsilon for x to determine an appropriate value for N.

Discussion Status

The discussion includes various viewpoints on the use of different methods to approach the problem. Some participants emphasize the importance of rigor in mathematical proofs, while others advocate for flexibility in methods. The original poster indicates that their problem has been resolved, although the specifics of the resolution are not detailed.

Contextual Notes

There is an underlying tension between using intuitive methods versus formal definitions in mathematics, as well as a recognition of the original poster's limited experience with trigonometric functions. The discussion reflects a broader conversation about learning and applying mathematical concepts.

bluevires
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Hey guys

I'm having trouble proving this limit using delta-epsilon definition
I would appreciate some help if possible

<br /> \lim_{x\rightarrow \infty} \arctan(x)=\frac{\pi}{2}<br />

I know that in order for the statement to be true,
Assuming
Epislon>0
Then |f(x)-L|<Epsilon for x> N

but i havn't had much experience working with trignometric functions, so I don't know how should I set my N equals to, and how could I convert that to |f(x)-L|< Epsilon
 
Last edited:
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Do you have to use a delta-epsilon definition to solve your problem? Just thinking about the graph of arctan(x) the answer is obvious what happens as x approaches infinity. It seems like a stupid question if you can just come up with the answer in a couple second.
 
Mindscrape said:
It seems like a stupid question if you can just come up with the answer in a couple second.
The point of a calculus class is to learn calculus. If you can't use calculus to compute something "obvious", then how are you going to use calculus to compute something that isn't "obvious"? :-p


bluevires -- why not simply solve the inequality

| \arctan x - \pi / 2 | &lt; \epsilon

for x, to figure out what you should use for N?
 
Yeah, but the point of any math class should be to allow for any viable method to be used, and for math to be open.
 
Mindscrape said:
Yeah, but the point of any math class should be to allow for any viable method to be used, and for math to be open.
No, the point of a math class is to learn math.

Learning to use alternate methods is certainly a part of math, and is a good thing, but using alternate methods at the expense of learning the subject you're supposed to be learning is bad.

(I often advise doing the same problem multiple ways, if you can!)

And, a big part of mathematics is being able to back up your intuition with rigor when appropriate -- it was intuition that told you what the value of the limit should be, but what if someone didn't have as much faith in your intuition? (e.g. a co-worker... a teacher... your boss...)
 
thank you hurkyl, problem solved.
 

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