Proving a positive series converges

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Homework Help Overview

The discussion revolves around proving the convergence of two strictly positive series, {an} and {bn}, based on the limit of their ratio as n approaches infinity. The original poster is exploring the implications of the limit being a non-zero constant and is seeking clarity on how to approach the proof, particularly regarding the biconditional nature of the statement.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the proof requirements related to the convergence of the series and expresses confusion about the implications of the limit condition. Some participants suggest using comparison tests as a potential approach to the problem.

Discussion Status

The discussion is ongoing, with participants exploring different methods to tackle the proof. Guidance has been offered regarding the use of comparison, but there is no explicit consensus on the approach or resolution of the original poster's confusion.

Contextual Notes

The original poster is grappling with the biconditional nature of the convergence statement and the implications of the limit condition, indicating a need for further clarification on the assumptions involved.

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Homework Statement



Let {an}n≥1 and {bn}n≥1 be strictly positive series.
If the limit n-> infinity (an/bn) = c /= 0, then the \sum an converges iff \sum bn converges, n≥1

Homework Equations





The Attempt at a Solution



Since we know that lim (an/bn) = c, then
for all ε>0, \exists a natural number N s/t for all n≥N,
|an/bn - c| < ε.

Then suppose the \sum an converges but the \sum bn does not...

I'm trying to understand what to prove exactly.. so IF the limit of (an/bn) = c, THEN the 2 series converge.. but it's confusing me since there is the second iff... what do I prove first?
Also any advice on how to go about it?
 
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You know that the is an N such that:
<br /> \frac{a_{n}}{b_{n}}-c&lt;1<br />
Hence
<br /> a_{n}&lt;(c+1)b_{n}<br />
What now?
 
Should I use comparison?
 
Yes, comparison is good.
 

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