Proving Abelian Group Structure in C^A

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SUMMARY

The discussion revolves around proving the Abelian group structure of the set of functions from a set A to the complex numbers C, denoted as C^A. The participants emphasize the necessity of demonstrating closure, identity elements, and inverses for each function in C^A. They assert that the associativity and commutativity of function multiplication follow from the properties of the ring C. Additionally, the need for a clear understanding of group homomorphisms is highlighted as essential for addressing the second question posed in the homework.

PREREQUISITES
  • Understanding of Abelian groups and their axioms
  • Familiarity with function composition and properties
  • Knowledge of ring theory, specifically regarding complex numbers
  • Basic concepts of group homomorphisms
NEXT STEPS
  • Study the properties of Abelian groups in detail
  • Learn about function composition and its implications in group theory
  • Explore ring theory with a focus on complex numbers and their structures
  • Research group homomorphisms and their role in algebraic structures
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Mathematics students, particularly those studying abstract algebra, and anyone interested in understanding the structure of function spaces and group theory.

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Homework Statement



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The Attempt at a Solution



For the first question, since [f(a)][g(a)] is in C, can I just say that since C is a ring, it is an abelian group, then the four axioms are proven? Then just show closure? Probably not I'm guessing. Associativity of multiplying functions seems so fundamental to me that I really don't know what to do...

For the second question, shall I start by using composition of functions and then the properties of composition of a function and its inverse, and then go on about the identity function?
 

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I'd say question one is asking you to flesh out the group structure.

1. What's the identity element? (make sure it's a member of C^A).

2. For each element f, what's the inverse element? (make sure it's well defined
- namely, why can you find f^-1 for each f? )

Closure is trivial but should be mentioned, namely why is (fg) a well
defined member of C^A when f and g are?

Associativity (and Abelian-ness) of course follow from the properties of C,
but you should have a proof showing f(gh) =(fg)h.

For question 2. I don't know what A-hat is. What do you know
about group homomorphisms at this point?
 

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