Proving an exponent law in group theory

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Discussion Overview

The discussion revolves around the proof of the exponent law in group theory, specifically the equation ##x^a x^b = x^{a+b}##. Participants explore whether an induction argument is necessary for this proof or if a more intuitive approach suffices. The scope includes theoretical reasoning and mathematical justification.

Discussion Character

  • Debate/contested

Main Points Raised

  • Some participants question the necessity of an induction argument, suggesting that simply counting the number of x's on the left-hand side (LHS) suffices to conclude there are ##a+b## x's.
  • Others argue that this intuitive approach is essentially the same as the induction argument but lacks the detailed justification.
  • A participant notes that the argument involves more than just inspecting the symbolic expressions; it requires interpreting the notation and invoking the associative property of the group's multiplication.
  • Some participants assert that while the conclusion may seem "obvious," a rigorous approach would necessitate avoiding informal reasoning and employing an induction argument.
  • There is a question about whether the integers a and b are positive, which may affect the validity of the arguments presented.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether an induction argument is necessary. There are competing views on the sufficiency of intuitive reasoning versus formal proof methods.

Contextual Notes

The discussion highlights the dependence on the definitions of exponentiation in group theory and the assumptions regarding the nature of the integers involved (a and b). The necessity of the associative property is also noted as a critical aspect of the argument.

Mr Davis 97
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The textbook proves that ##x^a x^b = x^{a+b}## by an induction argument on b. However, is an induction argument really necessary here? Can't we just look at the LHS and note that there are a ##a## x's multiplied by ##b## x's, so there must be ##a+b## x's?
 
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That's the same as the induction argument, only without the details.
 
ShayanJ said:
That's the same as the induction argument, only without the details.
So the details are absolutely necessary?
 
Mr Davis 97 said:
The textbook proves that ##x^a x^b = x^{a+b}##
Can't we just look at the LHS and note that there are a ##a## x's multiplied by ##b## x's, so there must be ##a+b## x's?

If you look at the left hand side of that equation, you see two symbols "x" and on the right hand side you see one symbol "x". So the argument you are making involves more than inspecting the symbolic expressions on left and right hand sides. You are also making an interpretation of the symbolic notation in that equation as other symbolic notation and then you are implicitly making use of the associative property of the group's multiplication.
 
Mr Davis 97 said:
So the details are absolutely necessary?
No, not really, because it's "obvious" in this case. But if you want to be very picky, you have to avoid the "dots" and replace them by an induction argument. Additionally the associative property is required to justify the notation ##x^a## at all. So the answer is: it depends on how explicit you want to be.
 
Mr Davis 97 said:
The textbook proves that ##x^a x^b = x^{a+b}## by an induction argument on b. However, is an induction argument really necessary here? Can't we just look at the LHS and note that there are a ##a## x's multiplied by ##b## x's, so there must be ##a+b## x's?
Are a,b positive integers?
 

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